Free Fall Equation With Air Resistance. Resistance.” the force of air resistance f d = bv applying the second law to a falling object using the coordinates at the right, σf y = ma y ⇒ f g −f d = ma⇒ mg−bv = ma, where the mass/weight rule has been used. There is no exact relationship between the velocity of an object and the air resistance acting on it.
Therefore, the maximum height that a body covers to reach the ground is 313.6 m. The formula for acceleration due to gravity is 9.8 m/s 2, so if an object is in free fall (which is no air resistance), the only force acting on that object will be gravity, and the acceleration. That is, the force due to air resistance is numerically equal to some constant \( k\) times \( v\).
But in the atmosphere, the motion of a falling object is opposed by the aerodynamic drag.
Without the effect of air resistance, each object in free fall would keep accelerating by 9.80665 m/s (approximately equal to 32.17405 ft/s) every second. G is the free fall acceleration (expressed in m/s² or ft/s²). Fgravity = g ⋅ mearth ⋅ m1 d2. W h e r e m = m a s s o f t h e e a r t h, a n d g = t h e u n i v e r s a l g r a v i t a t i o n c o n s t a n t.
